how legend update with variable

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Sun Heat
Sun Heat am 23 Aug. 2019
Kommentiert: Sun Heat am 26 Aug. 2019
t=linspace(0.1,1,10)
legend ('0.1','0.2','0.3',......upto '1')
how legend update with variable 't' with there values on graph
  4 Kommentare
Bruno Luong
Bruno Luong am 23 Aug. 2019
Bearbeitet: Bruno Luong am 23 Aug. 2019
There is something called ARRAYFUN
legend_txt = arrayfun(@(x)sprintf('%.1f',x),t,'UniformOutput',0)
Sun Heat
Sun Heat am 26 Aug. 2019
thanks

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