Filter löschen
Filter löschen

Cell and String manipulation

1 Ansicht (letzte 30 Tage)
susan
susan am 10 Sep. 2012
Hi, I have A= <900x1> cell The cell contents are as follows:
AA
BB
CC
AA
BB
CC
.
.
.
1) I need to separate the above into blocks of 300. i.e. change the first 300 into the following:
AA1
BB1
CC1
...
Then the next 300 to AA2 BB2 CC2
And the following 300 to
AA3
BB3
CC3
2)So now I have A = {AA1} {BB1} {CC1} {AA1} {BB1} {CC1}... {AA2} {BB2} {CC2} i.e. I have sets of AA*, BB*, CC* that repeat. The first 300 have a suffix of 1, and so on..
I have thus 300 CCs. I have another variable h = 300x1 which is made up of ones and zeros.
h = [ 1 0 1 ...]
i.e. every CC in A has a corresponding h
I need to do the following
if h = 1, then the set (AA*,BB*,CC*) preceding the corresponding CC become AA1c, BB1c, CC1c.
if h = 0, then the set preceding the corresponding CC become AA1ic, BB1ic, CC1ic
So A = {AA1c} {BB1c} {CC1c} {AA1ic} {BB1ic} {CC1ic}... {AA2c} {BB2c} {CC2c}
I am not sure if I managed to convey the issue here so please let me know if I hav'nt and I will try to better explain.
Thank you.

Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 10 Sep. 2012
Bearbeitet: Andrei Bobrov am 10 Sep. 2012
a0 = cellstr(('1':'3')');
a1 = {'';'i'};
[i1,i2]=ndgrid(1:3,h+1);
out = strcat(A,a0(i1(:)),a1(i2(:)),'c');

Weitere Antworten (2)

susan
susan am 11 Sep. 2012
Actually I need a couple of changes.
A =
'AA' 'BB' 'CC' 'AA' 'BB' 'AA' 'BB' 'CC' 'AA' 'BB' 'CC' 'AA' 'BB' 'CC' 'AA'
%------
h =
1 0 1 1 0
%------
Right now out =
'AA1ic'
'BB2ic'
'CC3ic'
'AA1c'
'BB2c'
'AA3c'
'BB1ic'
'CC2ic'
'AA3ic'
'BB1ic'
'CC2ic'
'AA3ic'
'BB1c'
'CC2c'
'AA3c'
What I need is:
'AA1ic'
'BB1ic'
'CC1ic'
'AA1c'
'BB1c'
'AA1c'
'BB2ic'
'CC2ic'
'AA2ic'
'BB2ic'
'CC2ic'
'AA3ic'
'BB3c'
'CC3c'
'AA3c'
i.e. blocks of 1s, 2s and 3s NOT blocks of 1,2,3...
Thank you again!
  3 Kommentare
susan
susan am 11 Sep. 2012
Actually can't because I need to preserve the order of h.
John Petersen
John Petersen am 21 Nov. 2012
Bearbeitet: John Petersen am 30 Nov. 2012
the value of h is already embedded in the AA's, BB's, etc. so why do you need h anymore?

Melden Sie sich an, um zu kommentieren.


susan
susan am 11 Sep. 2012
I am probably being very daft here but need to figure out how to translate the answer for my actual data..
A=<1152x1> cell h=288 x 1
A = 'TSTR' 'Co02' 'RT ' 'TEND' 'TSTR' 'Co19' 'RT ' 'TEND'...
I basically need the first 384 values with the suffix 1, then the next 384 trials with suffix 2, and the last with 3.
Each trial has a single h value associated with it, so I have 288 (1152/4) of those..
Sorry for not getting this..

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by