Dynamic Array update without for loop

Dear All,

Is there any possibilty to run below mentioned code without using FOR loop as run time is higher with loops,

A=rand(100000,1);B=rand(100000,1);
Out=zeros(length(A),1);
for i=2:length(A)
Out(i)=0.1*Out(i-1)+(0.9*(A(i-1)-B(i)));
end

[Walter Roberson]

I suspect that filter() or related functions could be used

[Vick]

Hi Walter, Can you give some example code for this function. You are right that the function is a kind of transfer function. I don't know how to give the filter constant in this case is (0.1), taking from the pervious time and (1-0.1) taking from other calculation.

Answer 1

[Matt J]

X=0.9*(A(1:end-1)-B(2:end));

Out=[0;  filter(1,[1,-0.1],X)];