How to take all output from while loop?

I have while loop in following coding. it count data for a year. i am no able to take all one year data. It just shows last answer. I also tried double command it doesn't work too. Please help me how to take all one year data.

Thanks in advance.

clc;
clear;
clear all;
pv = xlsread('POWER PV');
p = size (pv,1);
load = xlsread('LOAD');
pemfc = xlsread('PEMFC 1');
l = size (pemfc,1);

i = 243.72; %(731 Wh)
h2 = 11698.56; %(48 Saat için h2 depolama)
for sun = 1:1:p ;
if load(sun,1) < pv (sun,1);
    x = pv(sun,1)-load (sun,1); 
    
elseif load(sun,1) > pv (sun,1);
    y = load(sun,1) - pv (sun,1);
   v = pemfc(find( pemfc > y(:,1) , 1 ) ); % very important .....
    x = -v ;
    while  h2 > 0
    g = h2 + (x(sun,1)*(243.71/731)); 
    h2 = g;
    h2;
    end
else
    x = 0;
end

n(sun,1) = double (x);
end 

Answer 1

[Star Strider]

I cannot run your code without your files.

However see if this solves the problem with your while loop:

    k = 1;
    while  h2 > 0
        g = h2 + (x(sun,1)*(243.71/731)); 
        h2 = g;
        h2v(k) = h2;
        k = k + 1;
    end

or, if ‘h2’ is not a scalar, save it as a cell array:

    k = 1;
    while  h2 > 0
        g = h2 + (x(sun,1)*(243.71/731)); 
        h2 = g;
        h2v{k} = h2;
        k = k + 1;
    end

Experiment to get the result you want.

[Mohammad Sulaiman Stanekzai]

Thank you so much, It worked perfectly.

[Star Strider]

As always, my pleasure!

[Mohammad Sulaiman Stanekzai]

I also have a problem in x(sun,1) section it takes last value of x = -v but i have 8784 different value for x. I mean x(sun,1) have to take x values one by one. Please help me.

 while  h2 > 0
    g = h2 + (x(sun,1)*(243.71/731)); 
    h2 = g;
    h2;

[Star Strider]

Your code is a bit confusing.

This assignment:

g = h2 + (x(sun,1)*(243.71/731)); 

will use whatever the value of ‘sun’ is in that iteration. Revising slightly my original Answer, perhaps:

    while  h2 > 0
        g = h2 + (x(sun,1)*(243.71/731)); 
        h2 = g;
        h2v(sun) = h2;
    end

is what you want.

If you want ‘h2v’ to be a column vector, assign it as:

    h2v(sun,:) = h2;

[Mohammad Sulaiman Stanekzai]

Dear sir, in the following assignment x is calculating 8784 values. By the way sun in index and equal 1:1:p, here p is values which it takes from excel file.

elseif load(sun,1) > pv (sun,1);
    y = load(sun,1) - pv (sun,1);
   v = pemfc(find( pemfc > y(:,1) , 1 ) ); % very important .....
    x = -v ;
   

in the folowing assignment i want h2 for every x value which i found above but it just take the last value of x.

k = 1;
    while  h2 > 0
        g = h2 + (x(sun,1)*(243.71/731)); 
        h2 = g;
        h2v(k) = h2;
        k = k + 1;
        

i also tried your last coding but didn't work. Please help me

[Star Strider]

If my previous code did not do what you want, I have no idea what the problem is. I have no other solutions. I do not have your data, or an example of what you want the result to be.

Guessing here.

Perhaps this is what you want:

elseif load(sun,1) > pv (sun,1);
    y = load(sun,1) - pv (sun,1);
    v = pemfc(find( pemfc > y(:,1) , 1 ) ); % very important .....
    x = -v ;
    if  h2 > 0
        g = h2 + (x(sun,1)*(243.71/731)); 
        h2 = g;
        h2v(sun) = h2;
    end
else

It replaces your while loop with an if block.