Building the legend according to user input.

Hey all,

Hope everyone doing good.

I have a small question here.

I need to get the legend according to input.

Below is my code;

n = 50;
[f,T1, X] = Samplemodel_Instat('Measuring_Data.mat');
%X = {[ 2 4 6] ['Node2' 'Node4' 'Node6']};
for plotnumber = 1:n
  c = find(X{1,1} == plotnumber,1);
  if ~isempty(c)
    c = plotnumber;
    if n <= 3 
      plot(f(1:150:end)/3600,T1(c,1:150:end),'Color',[0.831372559070587 0.815686285495758 0.7843137383461]);
% legend(X{1+1}(col,row));
%plot(f(1:200:end)/3600,T1(c,1:200:end),'DisplayName',X{1+1}(col,row));
    elseif n > 3
      if c >= 1 && c <= ceil(n./4)
        plot(f(1:200:end)/3600,T1(c,1:200:end),'Color',[0.25 0.25 0.25],'LineWidth',4,'LineStyle','-.','MarkerFaceColor',[1 1 1],'Marker','none');
       % legend(X{1+1}(col,row));
       %plot(f(1:200:end)/3600,T1(c,1:200:end),'DisplayName',X{1+1}(col,row));
      elseif c > (ceil(n./4)) && c <=  ceil(n./2)
        plot(f(1:200:end)/3600,T1(c,1:200:end),'Color',[0.952941179275513 0.87058824300766 0.733333349227905],'LineWidth',2,'MarkerFaceColor',[1 1 1],'Marker','s');
% legend(X{1+1}(col,row));
%plot(f(1:200:end)/3600,T1(c,1:200:end),'DisplayName',X{1+1}(col,row));
      elseif c > (ceil(n./2)) && c <= ceil(3*n./4)
        plot(f(1:200:end)/3600,T1(c,1:200:end),'Color',[0.31 0.31 0.31],'LineWidth',2,'LineStyle','-','Marker','d','MarkerFaceColor',[1 1 1]);
   % legend(X{1+1}(col,row));
   %plot(f(1:200:end)/3600,T1(c,1:200:end),'DisplayName',X{1+1}(col,row));
      elseif c > (ceil(3*n./4)) &&  c <= n
        plot(f(1:150:end)/3600,T1(c,1:150:end),'Color',[0.831372559070587 0.815686285495758 0.7843137383461]);
       % legend(X{1+1}(col,row));
       %plot(f(1:200:end)/3600,T1(c,1:200:end),'DisplayName',X{1+1}(col,row));
      end
    end
  end
end

Here I need to get the legend everytime for the respective c.

For an example if c = 2, legend should be Oil. You can see how c become 2 in X above.

I hope that it is eary to understand.

Any suggestions and answered are most welcomed.

Thanks in advance

Answer 1

[Jon]

It is a little hard to understand all of the details of what you are doing in your code, and what exactly you want to produce for plots. If I am understanding correctly, I think you should be able to do what you want by setting the DisplayName property when you plot the line.So put your possible legend names in a cell array e.g. names = {'Oil','Air','Material'}, and then index appropriately when you plot the line, to set the DisplayNamso something like,

plot(f(1:200:end)/3600,T1(c,1:200:end),'DisplayName',names{k})

, where k is the appropriate index.

[surendra kumar Aralapura mariyappa]

@ Jan,

,' where k is the appropriate index'.

This is what I am looking for exactly,

X = {[ 2 4 6] ['Node2' 'Node4' 'Node6']};

If I got to know the indicies of X{1}, before the solver enter the plot function, I can use that indicies to get the suitable legend to that number like X{2}(). For an example if c = 2, then legend is Node2.

Let's consider c = 4, then it's index is X{1}(1,2) this I can write as X{1}(row, col).

So in your solution I can write it as

plot(f(1:200:end)/3600,T1(c,1:200:end),'DisplayName',X{1+1}{col, row)

Or else, kindly tell me or give me an hint, to get the legend to my above quwstion. your collegaue has given me a solution, but it is not working as I intended.

I still remember that you answered to one of the questions similar to my question. But I am not able to get it again.

Hope you can understand now

[Jon]

I sorry but I am still having difficulty understanding your application. If I am understanding correctly however I would suggest the following.

First use two separate variables in place of your X, this will make the indexing much simpler and clearer. So for example define

crvIdx = [2 4 6]; % curve index
crvName = {'Node2','Node4','Node6'} % or maybe {'oil','gas','air'} whatever you want the labels to be

then you can use the find function to match the curve index to the plot number

c = find(crvIdx==plotnumber)

and when it comes time to set the legend name you would do something like

plot(f(1:200:end)/3600,T1(c,1:200:end),'DisplayName',crvName{c}

by the way, your intitial code fragment, which I list below, does not make sense to me

n = 50;
[f,T1, X] = Samplemodel_Instat('Measuring_Data.mat');
%X = {[ 2 4 6] ['Node2' 'Node4' 'Node6']};
for plotnumber = 1:n
  c = find(X{1,1} == plotnumber,1);
  if ~isempty(c)
    c = plotnumber;
    if n <= 3 
      plot(f(1:150:end)/3600,T1(c,1:150:end),'Color',[0.831372559070587 0.815686285495758 0.7843137383461]);

First you assign n = 50, so it is a constant value, and then later you check if n<=3, since n will always be 50, this condition would never be true, so I assume this isn't what you intended.

Second you first assign a value to c using the find function, c= find{X{1,..., and then you say if if ~isempty(c), c= plotnumber. So if it finds a value of c, c will not be empty, and then you immediately reassign it to equal the plot number. In this case why bother finding out where c matches, if whenever it finds something you immediately overwrite it. I guess this isn't what you had intended either

[surendra kumar Aralapura mariyappa]

@Jan

Thank you for your kindness. Actually I was bit confused. Because, I was stressed out myself while doing this. Then I got to know my mistakes. Now It is working properly. All your collegaues helped me out a lot.

Anyways thank you once again.