Plot 2D constraints

I have an equation (a-b)x+(c-b)y <= d and i would like to plot 20 instances of this equation.

The limits of the plot are set from -5 to 5. I have already a set of values for the a,b,c,d

Any ideas?

My code so far is:

x = [-5:0.1:5];
L = 20;
hold off
for i=1:L
    y = (d-x*(a-b))/(c-b)
    plot(x,y)
    hold on
end

[Gani]

You are not changing the values of Y inside the loop. Hence you will get same plot in each iteration.

Answer 1

[Star Strider]

You do not need the loop.

Try this:

x = linspace(-5, 5, 20);
L = 20;
y = (d-x*(a-b))/(c-b);
plot(x,y)

[Jack Haratsi]

Thank you for your answer but I think i expressed my question wrong.

The variables a,b,c,d are described by vectors of 20 elements each.

For each x,y variable, the equation should be given by a line in an x,y plot and that's why i used the loop.

The x,y are to be ploted in order to graph the blue lines showcased below:

[Star Strider]

My pleasure.

Yes, you did.

Knowing what a, b, c, and d are, and how they relate to the lines you want to plot, would help immensely. Are they the respective ends of the lines? Are they slopes and intercepts? Something else?

[Jack Haratsi]

They should be the ends of the lines. They should be treated as ''constraints'' that determine the domain at which i have a feasible solution.

Right now, my plot looks something like that, and i am not sure if it is correct:

[Star Strider]

What are the ends of the lines?

How should the lines be defined in terms of a, b, c, and d?

EDIT —

Should they be plotted as:

plot([a(:) b(:)]', [c(:) d(:)]')

Note that this will produce the series of straight lines that you likely want. The question is how to assign the vectors to the matrices here.