I=[-40 -30 -20 -10 0 10 20 30 40];
w=[0.035 0.5 1 1.25 1.5];
h=1.57;
I_len=length(I);
w_len=length(w);
for b=1:w_len
d=w(b);
for c = 1:I_len
a = I(c);
T=215.3*a^2*d^-1.5*h^-1;
end
end
This is my code.
how do I tabulate the results of a,d,h,T and plot the graph for the same?

 Akzeptierte Antwort

KSSV
KSSV am 18 Jun. 2019

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I=[-40 -30 -20 -10 0 10 20 30 40];
w=[0.035 0.5 1 1.25 1.5];
h=1.57;
I_len=length(I);
w_len=length(w);
T = zeros(w_len,I_len) ;
for b=1:w_len
d=w(b);
for c = 1:I_len
a = I(c);
T(b,c)=215.3*a^2*d^-1.5*h^-1;
end
end
[X,Y] = meshgrid(I,w) ;
surf(X,Y,T)

4 Kommentare

Sachin Shridhar Bhat
Sachin Shridhar Bhat am 18 Jun. 2019
Can you explain me what did you do in the above code?
because I had tried with mesh grid and had used sliceomatic and I got an error with it.
so can you tell me?
KSSV
KSSV am 18 Jun. 2019
It is self explanatory.......variables I, w are introduced in meshgrid to make it a matrix. T is initialized. In fact, you need not to use meshgrid, with T as matrix itself, it can be plotted. Simply try:
surf(I,w,T)
Sachin Shridhar Bhat
Sachin Shridhar Bhat am 18 Jun. 2019
Okay thank you
KSSV
KSSV am 18 Jun. 2019
Thanks is accepting and/or voting the answer. :)

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Weitere Antworten (1)

Shubham Sangle
Shubham Sangle am 18 Jun. 2019

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Your question is not clear.
1:Graph between what parameters you want to plot?
2:In your For loop you are assigning every element of array to variable d and b. You are neither using them anywhere nor storing them. what you want to do with those variable?

1 Kommentar

Sachin Shridhar Bhat
Sachin Shridhar Bhat am 18 Jun. 2019
1 - Graph between a,d,h,T
2- In for loop I am assigning each variable of w to d and I to a . And of course I am using those values to calculate the final T value in the equation below.

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