I need some help with arrayfun

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jasmine
jasmine am 10 Jun. 2019
Beantwortet: the cyclist am 12 Jun. 2019
I have this data from a mice experiment:
  • Reaction Time
  • Response Made (which can be 0,1 or 2)
  • Visual contrast (one of 9 possible values)
I would like to use arrayfun to calculate the mean reaction time for each of the 9 values of visual contrast when the response made was 2.
Each set of data is written in a separate Matlab table.
Thank you.
  8 Kommentare
the cyclist
the cyclist am 10 Jun. 2019
Well, the main information I am trying to get at is the data types and how you are storing.
You make the statement "Each set of data is written in a separate Matlab table". That suggests to me that you have three variables of data type table. But your screen shot shows three columns of a single variable of data type double.
I'm just trying to sort this out, so that I don't suggest a solution that doesn't actually work for how your variables are stored.
jasmine
jasmine am 10 Jun. 2019
Sorry, yeah, they are normally stored as single double type.

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Antworten (2)

Steven Lord
Steven Lord am 10 Jun. 2019
I don't think arrayfun is the tool you want to use here. Instead groupsummary seems like a better fit.
  3 Kommentare
jasmine
jasmine am 10 Jun. 2019
Pressuming that the response made is always = 2 (also making it a bit easier this way), how can I get the mean reaction time for each of the 9 visual contrasts?
Steven Lord
Steven Lord am 10 Jun. 2019
Take a look at the "Multiple Grouping Variables" and "Multiple Grouping Vectors for Vector Input" examples on the documentation page to which I linked. You should be able to adapt these to your data.
Instead of computing the mean Weight for people grouped by Gender and whether or not they are Smokers, you could compute the mean ReactionTime for items grouped by Response and Contrast.

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the cyclist
the cyclist am 12 Jun. 2019
I believe that groupsummary is for data stored in tables only. You can do what you want with
[sortedResponses,~,idx] = unique(R(:,2));
meanTimes = accumarray(idx,R(:,1),[],@mean);
Here, R is your original data, and meanTimes will have the mean values for the sortedResponses.
You could also just do
mean(R(R(:,2)==2),1)

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