Please anyone help me with the error!

3 Ansichten (letzte 30 Tage)
Gaurav Srivastava
Gaurav Srivastava am 28 Mai 2019
Kommentiert: KSSV am 28 Mai 2019
Please write the code-Screenshot (14).png

Akzeptierte Antwort

madhan ravi
madhan ravi am 28 Mai 2019
fprintf('The potential difference is \n')
disp(potential)

Weitere Antworten (1)

KSSV
KSSV am 28 Mai 2019
potential = double(potential) ;
fprintf('the potential difference is = %f\n',potential) ;
Your variable potential is in syms...convert it to double. Read about double.
  3 Kommentare
Gaurav Srivastava
Gaurav Srivastava am 28 Mai 2019
Still not working sir!Screenshot (15).png
KSSV
KSSV am 28 Mai 2019
You should not attach code as image.......copy the code here.

Melden Sie sich an, um zu kommentieren.

Produkte


Version

R2017a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by