How to convert binary bits of a vector, say m, after rotating it left by 1 bit, into decimal ?

m = [16, 10];  % 1x2 array
a = fi(m, 0, 8, 0); 
b = bin(bitrol(a, 1));  % Left rotate a by 1 bit 
b = 00100000   00010100     %  output ,  1x19 char
c = bin2dec(b)    % decimal representation of b   
c = 8212       % output, not same as array 'm' 

How to get back m ??

Please help!

[Abdul Gaffar]

A small improvement:

m = [16, 10]; % 1x2 array

a = fi(m', 0, 8, 0); % m is changed to m' , where ' denotes transpose

b = bin(bitrol(a, 1)); % Left rotate a by 1 bit

% b = 00100000 00010100 % output , 1x19 char

c = bin2dec(b) % decimal representation of b

d = c' % Added

% d = [32, 20] % output in array format

Thanks!

Answer 1

[David Hill]

m = [16; 10];  %use column vector
a = fi(m, 0, 8, 0); 
b = bin(bitrol(a, 1)); 
c = bin2dec(b);

[Abdul Gaffar]

Thanks, this works.

Now, how to do the same, if m is a matrix?

[David Hill]

a=fi(m(:),0,8,0);
b = bin(bitrol(a, 1)); 
c = reshape(bin2dec(b),size(m));

[Abdul Gaffar]

Yes, it works.