Using the length() in a for loop
9 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi I have the following code which I am trying to loop. the loop isn't working however and I don't know why
PVsupply = [0 0 0 0 0 0.05 0.1 0.11 0.13 0.13 0.15 0.15 0.15 0.15 0.145 0.145 0.14 0.135 0.08 0.05 0 0 0 0];
hourly_daily_PV = PVsupply(:);
hourly_annual_PV = repmat(hourly_daily_PV,365,1);
WTsupply = [10 10 10 10 25 25 25 15 15 15 15 15 15 15 35 35 35 35 35 10 10 10 10 10 ];
hourly_daily_WT = WTsupply(:);
hourly_annual_WT = repmat(hourly_daily_WT,365,1);
number_panels = 1:10:100;
number_turbines = 1:1:5;
for idx_number_panels = 1:length(number_panels) % range of PV panel units examined
for idx_number_turbines = 1:length(number_turbines) % range of wind turbine units examined
for number_batteries = 1:5 % range of battery units examined
for h=2:25 %# hours
hourly_total_RES(idx_number_panels,idx_number_turbines,number_batteries, h) = hourly_annual_PV(h)*number_panels(idx_number_panels) + hourly_annual_WT(h)*number_turbines(idx_number_turbines);
end
end
end
end
5 Kommentare
Oleg Komarov
am 20 Aug. 2012
I don't get any error, nor the size is [1 1 1 5] with the data and script you supplied.
Antworten (1)
Azzi Abdelmalek
am 20 Aug. 2012
i am not getting any errors; before running your code use
clear
if it does'nt work check if any of your variables are not shadowed by any function or file with the same name in your working folder
0 Kommentare
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!