Coeff & constants of a symbolic equation

syms a b c
exp=[-a-2*b-3*c+2, 4*b-c, -5*a+3]
I need the coefficient matrix in the form
% Coef_matrix=[ -1, -2, -3, 2; 0, 4, -1, 0; -5, 0, 0, 3];
How do I get this?
I can get the first line from the following syntax (from a previous blog), but there is an error when I try to do the second & third lines (i.e. j=1:3) as there is a 'zero' which it wont recognize
xx = symvar(exp) %find the variables in expression 'exp'
Coef_matrix = zeros(numel(exp),numel(xx));
for j = 1
[v1,v2] = coeffs(exp(j),xx);
Coef_matrix(j,ismember(xx,v2)) = v1(1:numel(xx));
end
And when I get the coefficients, I cant get the constant term at the end.
The solution should be able to scale up for more variables, as this is a simplified version of my problem. Thanks

 Akzeptierte Antwort

Oleg Komarov
Oleg Komarov am 20 Aug. 2012
Bearbeitet: Oleg Komarov am 20 Aug. 2012

0 Stimmen

syms a b c
exp = [-2*b-a-3*c+2; -c+4*b; -5*a+3];
xx = symvar(exp);
Coef_matrix = zeros(numel(exp),numel(xx)+1);
for j = 1:3
[v1,v2] = coeffs(exp(j),xx);
[idx,loc] = ismember(v2,xx);
idx(end) = true;
loc(loc == 0) = 4;
Coef_matrix(j,loc) = v1(idx);
end

6 Kommentare

Mech Princess
Mech Princess am 20 Aug. 2012
Bearbeitet: Mech Princess am 20 Aug. 2012
Thanks, it works for the symbols.
-1 -2 -3
0 4 -1
-5 0 0
How do I get the constant term at the end?
-1 -2 -3 2
0 4 -1 0
-5 0 0 3
Thanks in advance
Azzi Abdelmalek
Azzi Abdelmalek am 20 Aug. 2012
Bearbeitet: Azzi Abdelmalek am 20 Aug. 2012
why don't you change your expression
syms a b c d
exp = [-2*b-a-3*c+2*d; -c+4*b; -5*a+3*d]
then just ignore d
Mech Princess
Mech Princess am 20 Aug. 2012
Bearbeitet: Mech Princess am 20 Aug. 2012
Thanks. This seems great if it was a straight fwd Qn. I dont have control of the immediate expression. My actual problem is way more complicated.
"exp" is the derivative of another expression "LD_new".
LD_new is arrived at by substituting expression "st" in "LD".
LD is arrived at by summing all the expressions of "LD0".
LD0 is my input vector multiplied by the variables.
Is there an easier way to do this? Thanks again
Oleg Komarov
Oleg Komarov am 20 Aug. 2012
@Mech: I edited the code to generate the coeff matrix with the constant term as well.
Mech Princess
Mech Princess am 20 Aug. 2012
Thanks a million. I've been working on this for weeks!
Oleg Komarov
Oleg Komarov am 20 Aug. 2012
You weren't far from the solution.

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