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How can I solve for coupled differential equations?

1 Ansicht (letzte 30 Tage)
onamaewa
onamaewa am 16 Mai 2019
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
How can I solve for the 's in the system of differential equations?
I have:
m1 = 12; m2 = 24; K1 = 6000; K2 = 3450; B1 = 40; B2 = 28; F = 5;
My equations are:

Antworten (2)

Sulaymon Eshkabilov
Sulaymon Eshkabilov am 31 Mai 2019
Bearbeitet: Sulaymon Eshkabilov am 31 Mai 2019
if FREQ = 0 ... 1000 Hz. Then you will have 1001 solutions with a freq step of 1 Hz.
e.g.
f = 0:1000;
F = 5* 5 * (1i * 2 * pi * f);
for ii =1:numel(F)
ICs = [0; 0; 0; 0]; % Initial Conditions
ODE=@(t,x)([x(2); (1/m1)*(F(ii)-B1*x(2)+B1*x(4)+K1*x(3)); x(4);...
(1/m2)*(-(B1+B2)*x(4)+B1*x(2)-(K1+K2)*x(3)+K1*x(1))]);
[t, x]=ode45(ODE, ts, ICs, []);
plot(t, x(:,1), 'b', t, x(:,2), 'r', t, x(:,3), 'g', t, x(:,4), 'k'), hold on
end
Good luck

Sulaymon Eshkabilov
Sulaymon Eshkabilov am 16 Mai 2019
Hi Brandon,
An easy and fast way of solving this coupled system is to use ODEx (ode23, ode45, ode113, etc) solvers. Here is one of the quick solution scripts:
m1 = 12; m2 = 24; K1 = 6000; K2 = 3450; B1 = 40; B2 = 28; F = 5;
ODE=@(t,x)([x(2); (1/m1)*(F-B1*x(2)+B1*x(4)+K1*x(3)); x(4);...
(1/m2)*(-(B1+B2)*x(4)+B1*x(2)-(K1+K2)*x(3)+K1*x(1))]);
ts = [0, 1]; % Time space
ICs = [0; 0; 0; 0]; % Initial Conditions
[t, x]=ode45(ODE, ts, ICs, []);
plot(t, x(:,1), 'b', t, x(:,2), 'r', t, x(:,3), 'g', t, x(:,4), 'k')
  5 Kommentare
Sulaymon Eshkabilov
Sulaymon Eshkabilov am 31 Mai 2019
You said frequency 0 .. 1000 Hz that is for your external excitation force F? Let's say F = 10sin(f*t), where f is your frequency. Is that what you mean or what? ... Math is needed.
onamaewa
onamaewa am 31 Mai 2019
Bearbeitet: onamaewa am 31 Mai 2019
Sorry, I forgot to add that: F = 5 * (1i * 2 * pi * FREQ)

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