evalin('ca​ller','mfi​lename') does not work.

5 Ansichten (letzte 30 Tage)
raym
raym am 12 Mai 2019
Beantwortet: Walter Roberson am 13 Mai 2019
function out = cdc
out = evalin('caller','mfilename');
end
This fucntion returns the 'cdc', not the caller's mfilename.
  2 Kommentare
Rik
Rik am 12 Mai 2019
Why don't you use mfilename directly in the caller? Alternatively you can do something similar with dbstack.
raym
raym am 12 Mai 2019
dbstack does not five the full path to the function.
Now I have used mfilename in caller. I'm just curious about how the mfilename works.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Rik
Rik am 12 Mai 2019
Bearbeitet: Rik am 13 Mai 2019
Depending on your release you can get the complete names including the path from dbstack (in v6.5 you couldn't, but already since v7.0 you can). As the doc describes:
dbstack(___, '-completenames')
outputs the fully qualified name of each function in the stack.

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 13 Mai 2019
"evalin('caller', expression) finds only variables in the caller's workspace; it does not find functions in the caller. For this reason, you cannot use evalin to construct a handle to a function that is defined in the caller."
If I recall correctly mfilename is implemented by defining a function in each file.

Kategorien

Mehr zu Install Products finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by