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Cut Out Data for Analysis

5 Ansichten (letzte 30 Tage)
JamJan
JamJan am 6 Mai 2019
Beantwortet: dpb am 6 Mai 2019
Hello,
I have these kind of continuous Matrices with data (like 1000's of rows and always 8 columns):
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
9,31000000000000 5,10000000000000 0 0 0 0 0 0
4,24000000000000 13,6600000000000 0 2,15000000000000 0 0 0 0
4,27000000000000 2,43000000000000 4,48000000000000 3,34000000000000 1,96000000000000 1,96000000000000 0 0
-0,780000000000001 -0,390000000000001 2,76000000000000 1,25000000000000 2,47000000000000 2,47000000000000 0 0
-5,17000000000000 -6,51000000000000 0 1,10000000000000 2,02000000000000 2,02000000000000 0 0
-4,50000000000000 -6,35000000000000 0 0,230000000000000 1,48000000000000 1,48000000000000 1,10000000000000 0
0,640000000000000 -3,56000000000000 -0,470000000000001 0 1,84000000000000 1,84000000000000 0,230000000000000 2,19000000000000
-8,01000000000000 -1,19000000000000 0 0,209999999999999 3,31000000000000 3,31000000000000 0,220000000000000 0,610000000000000
0 -3,19000000000000 -1,05000000000000 0,210000000000001 3,35000000000000 3,35000000000000 0,770000000000000 0,750000000000000
0 0 -5,72000000000000 -0,650000000000000 5 5 1,92000000000000 1,45000000000000
0 0 0 -2,66000000000000 3,69000000000000 3,69000000000000 4,04000000000000 2,76000000000000
0 0 0 -0,989999999999999 -5,27000000000000 -5,27000000000000 3,99000000000000 0,250000000000000
0 0 0 -1,21000000000000 -7,48000000000000 -7,48000000000000 -2,31000000000000 -2,71000000000000
0 0 0 -2,98000000000000 -9,90000000000000 -9,90000000000000 -8,74000000000000 -5,30000000000000
0 0 0 0 -2,47000000000000 -2,47000000000000 -1,22000000000000 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0
I want to cut out each part these kind of changes happen, so:
9,31000000000000 5,10000000000000 0 0 0 0 0 0
4,24000000000000 13,6600000000000 0 2,15000000000000 0 0 0 0
4,27000000000000 2,43000000000000 4,48000000000000 3,34000000000000 1,96000000000000 1,96000000000000 0 0
-0,780000000000001 -0,390000000000001 2,76000000000000 1,25000000000000 2,47000000000000 2,47000000000000 0 0
-5,17000000000000 -6,51000000000000 0 1,10000000000000 2,02000000000000 2,02000000000000 0 0
-4,50000000000000 -6,35000000000000 0 0,230000000000000 1,48000000000000 1,48000000000000 1,10000000000000 0
0,640000000000000 -3,56000000000000 -0,470000000000001 0 1,84000000000000 1,84000000000000 0,230000000000000 2,19000000000000
-8,01000000000000 -1,19000000000000 0 0,209999999999999 3,31000000000000 3,31000000000000 0,220000000000000 0,610000000000000
0 -3,19000000000000 -1,05000000000000 0,210000000000001 3,35000000000000 3,35000000000000 0,770000000000000 0,750000000000000
0 0 -5,72000000000000 -0,650000000000000 5 5 1,92000000000000 1,45000000000000
0 0 0 -2,66000000000000 3,69000000000000 3,69000000000000 4,04000000000000 2,76000000000000
0 0 0 -0,989999999999999 -5,27000000000000 -5,27000000000000 3,99000000000000 0,250000000000000
0 0 0 -1,21000000000000 -7,48000000000000 -7,48000000000000 -2,31000000000000 -2,71000000000000
0 0 0 -2,98000000000000 -9,90000000000000 -9,90000000000000 -8,74000000000000 -5,30000000000000
0 0 0 0 -2,47000000000000 -2,47000000000000 -1,22000000000000 0
How can I do this?

Akzeptierte Antwort

dpb
dpb am 6 Mai 2019
x=x(any(x,2),:);

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