2nd Order Newtonian Formulation

X = I; % independent variable

Y = J'; % have to transpose the vector

a = length(X) % # of data points given

A - zeros(a) % creates an empty matrix

for c = 1:a

for r =1:a

if c == 1

A(r,c) = 1;

elseif c <= r

A(r,c)

end

end

end

b = A\Y

disp(A)

disp(Y)

disp(b)

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You don't get values for I and J, my teacher only said which one is the independent variable and which one is the dependent variable, so I am confused how you can get real number out of this code.