How can we explain this error?

First call no problem second call an error message.
>> datenumber = datevec('06/08/2012 15:20','dd/mm/yyyy HH:MM');
>> datenumber = datevec('06/08/2012 15:20','dd/mm/yyyy HH:MM');
Error using dtstr2dtvecmx
Failed on converting date string to date number.
Error in datevec (line 119)
y = dtstr2dtvecmx(t,icu_dtformat);
>> datenumber = datevec('06/08/2012 15:20','dd/mm/yyyy HH:MM');
>> datenumber = datevec('06/08/2012 15:20','dd/mm/yyyy HH:MM');
Error using dtstr2dtvecmx
Failed on converting date string to date number.
Error in datevec (line 119)
y = dtstr2dtvecmx(t,icu_dtformat);
>> datenumber = datevec('06/08/2012 15:20','dd/mm/yyyy HH:MM');
119 y = dtstr2dtvecmx(t,icu_dtformat);
>> datenumber = datevec('06/08/2012 15:20','dd/mm/yyyy HH:MM');
119 y = dtstr2dtvecmx(t,icu_dtformat);
Error using dtstr2dtvecmx
Failed on converting date string to date number.
Error in datevec (line 119)
y = dtstr2dtvecmx(t,icu_dtformat);

1 Kommentar

Wayne King
Wayne King am 9 Aug. 2012
I have no problem executing these lines. Can you please indicate which version of MATLAB, you are using.

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Antworten (2)

per isakson
per isakson am 10 Aug. 2012

0 Stimmen

I cannot reproduce the error with R2012a 64bit on Windows7.
>> datenumber = datevec('06/08/2012 15:20','dd/mm/yyyy HH:MM')
datenumber =
2012 8 6 15 20 0
Azzi Abdelmalek
Azzi Abdelmalek am 10 Aug. 2012
Bearbeitet: Azzi Abdelmalek am 10 Aug. 2012

0 Stimmen

check in your folder if a file named "datenumber" does'nt exist? if yes, rename it, restart matlab, i think it will be ok. or instead using a variable datenumber, change it.

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am 9 Aug. 2012

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