rank keywords using length

3 Ansichten (letzte 30 Tage)
ATHIRA P M
ATHIRA P M am 30 Mär. 2019
Kommentiert: dpb am 31 Mär. 2019
Dear sir,
I rank the keywords firstly according to its occurance.Next the output keywords should be ranked according to its length.how it is possible ?Please help me sir.the code i used is attached below.
fid = fopen('file.txt');
s=textscan(fid,'%s')
fclose(fid);
str=s{:}
[ii,jj,kk]=unique(str)
freq=hist(kk,(1:numel(jj))')'
[ii num2cell(freq)]
output:
'Audrey' [1]
'British' [1]
'Brussels' [1]
'Hepburn' [1]
'Ixelles,' [1]
'actress' [1]
'dancer' [1]
'fashion' [1]
'female' [1]
'film' [1]
'humanitarian' [1]
'icon' [1]
'legend' [1]
'model' [1]
'screen' [1]
'third-greatest' [1]

Akzeptierte Antwort

dpb
dpb am 30 Mär. 2019
[~,il]=sort(l,'descend');
K>> s(il)
ans =
16×1 cell array
{'third-greatest'}
{'humanitarian' }
{'Brussels' }
{'Ixelles,' }
{'British' }
{'Hepburn' }
{'actress' }
{'fashion' }
{'Audrey' }
{'dancer' }
{'female' }
{'legend' }
{'screen' }
{'model' }
{'film' }
{'icon' }
K>>
  2 Kommentare
ATHIRA P M
ATHIRA P M am 31 Mär. 2019
Dear sir,
it shows an error
undefined function or variable 'l'.
Error in keywords (line 8)
[~,il]=sort(l,'descend');
dpb
dpb am 31 Mär. 2019
"l" is the name of the variable holding the list -- I used "l" for the illustration, you need to use whatever it is you have-- "s" above.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by