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Is there a faster approach than \ operator to calculate the inverse of a lower triangular matrix?

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Benson Gou
Benson Gou on 20 Mar 2019
Dear All,
I have a big square lower triangular matrix A (6000 x 6000) which is very sprase with a density 0.05%, I am using Inv_A=A\eye(size(A)) to calculate the inverse of A. But I found it still takes more than 3 seconds. I am wondering if there exists a faster approach to calculate the inverse of A.
Thanks.
Benson

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