Undefined operator '*' for input arguments of type 'function_handle'.
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Akshay Pratap Singh
am 15 Mär. 2019
Kommentiert: Steven Lord
am 15 Mär. 2019
i wrote a following code. every thing is right but it shows error" Undefined operator '*' for input arguments of type 'function_handle'.
clear all
clc
syms x
h=4;
q=100;
delta=26;
phi=39;
kh=0;
kv=0;
psi=atan(kh/(1-kv));
da1=delta*(pi/180); pha1=phi*(pi/180);
m=pha1+da1;
b=pha1-psi;
c=psi+da1;
gma=18.4; nq=2*q/(gma*(x));
delta=26;
phi=39;
lam=0;
A=lam*nq/(1+nq);
alphac=atan((sin(m)*sin(b)+(sin(m)^2+sin(b)^2+sin(m)*cos(m)*sin(b)*cos(b)+A*cos(c)*cos(m)*sin(b))^0.5)/(A*cos(c)+sin(m)*cos(b)));
w=0.5*gma*(x)^2*(1/tan(alphac));
B=(x)*((1/tan(alphac))-lam);
ka1=((1+nq)*(1-A*tan(alphac))*(cos(b)-(sin(b)/tan(alphac))))/(cos(psi)*(cos(m)+tan(alphac)*sin(m)))
wt=w+q*B;
pa1 = matlabFunction(0.5*gma*x^2*ka1);
x=0:0.1:5;
R=(wt*(1-kv)-pa1*sin(da1))/cos(alphac-pha1);
za1=(0.5*R*cos(pha1)*(x/sin(alphac))-q*B*(lam*x+0.5*B)-(1/6)*(1/tan(alphac))*(gma/tan(alphac))*x^3)/(pa1*cos(da1))
plot(za1(x),x)
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Akzeptierte Antwort
Alex Mcaulley
am 15 Mär. 2019
Bearbeitet: Alex Mcaulley
am 15 Mär. 2019
You have some mix between symbolic functions and function handles. You need to choose one strategy. Try the following code, which uses only symbolic functions:
syms x
h=4;
q=100;
delta=26;
phi=39;
kh=0;
kv=0;
psi=atan(kh/(1-kv));
da1=delta*(pi/180); pha1=phi*(pi/180);
m=pha1+da1;
b=pha1-psi;
c=psi+da1;
gma=18.4; nq=2*q/(gma*(x));
delta=26;
phi=39;
lam=0;
A=lam*nq/(1+nq);
alphac=atan((sin(m)*sin(b)+(sin(m)^2+sin(b)^2+sin(m)*cos(m)*sin(b)*cos(b)+A*cos(c)*cos(m)*sin(b))^0.5)/(A*cos(c)+sin(m)*cos(b)));
w=0.5*gma*(x)^2*(1/tan(alphac));
B=(x)*((1/tan(alphac))-lam);
ka1=((1+nq)*(1-A*tan(alphac))*(cos(b)-(sin(b)/tan(alphac))))/(cos(psi)*(cos(m)+tan(alphac)*sin(m)))
wt=w+q*B;
pa1 = (0.5*gma*x^2*ka1); %changed
% x=0:0.1:5; %changed
R=(wt*(1-kv)-pa1*sin(da1))/cos(alphac-pha1);
za1=(0.5*R*cos(pha1)*(x/sin(alphac))-q*B*(lam*x+0.5*B)-(1/6)*(1/tan(alphac))*(gma/tan(alphac))*x^3)/(pa1*cos(da1))
fplot(za1,[0,5]) %changed
1 Kommentar
Steven Lord
am 15 Mär. 2019
Alternately if you want to use just function handles, you can't perform arithmetic with the function handles themselves but you can perform arithmetic on the values you receive when you evaluate the function handle.
f1 = @sin;
f2 = @cos;
x = 0:0.05:2*pi;
% Add the results of evaluating f1 and f2
willWork = @(x) f1(x)+f2(x);
figure
plot(x, willWork(x))
title('Will work')
% Try to add f1 and f2
willNotWork = @(x) f1+f2;
figure
plot(x, willNotWork(x)) % This line will error so ...
title('This line of code won''t be executed')
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