Hi all. Today I came across a function f(X,Y) = cos(2*pi*X)(1+3Y) + ((2*pi*y)^2)/2.
I thought this was a 3d function but apparently it's not. How do i plot this 2D function in MATLAB.
Is there a special function for handling potential functions in MATLAB? thank you very much

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Stephan
Stephan am 27 Feb. 2019
Bearbeitet: Stephan am 27 Feb. 2019

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f = @(X,Y) cos(2*pi.*X).*(1+3.*Y) + ((2*pi.*Y).^2)/2
fsurf(f)
func_sirf.PNG

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MatlabEnthusiast
MatlabEnthusiast am 27 Feb. 2019
Bearbeitet: MatlabEnthusiast am 27 Feb. 2019
so it indeed is 3d, right? does that mean the script had an error when it said 2d plot of the potential function?
thanks for the answer btw
Stephan
Stephan am 27 Feb. 2019
Bearbeitet: Stephan am 27 Feb. 2019
Yes, you have independent 2 input variables and a resulting value which is usually shown in the 3rd dimension. But of course you also can show this in 2D by using:
fcontour(f)
This results in:
If this answer was helpful, please accept it.
MatlabEnthusiast
MatlabEnthusiast am 27 Feb. 2019
yes. this is very helpful

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