Using loop to solve a summation

Is this correct

m=0

for m=0:1200

x=sum(1/factorial(m))

end

Answer 1

[Star Strider]

No, because you need to subscript ‘m’ and sum ‘x’ in each iteration.

However you do not need the loop:

m=0:1200;
x=sum(1./factorial(m))

Answer 2

[Kevin Phung]

No, you need to increment m with each step and add each partial sum.

This is what you need:

x= 0
for m = 0:1200
    x = x + 1/factorial(m(i))
end

[Colby Jennings]

why x if there is no x in the equation

[Ishmael Asad]

x is just the variable that will store that whole summation