Hi,
I have an array like:
0.2 2 3
1 3 4
1 4 6
0.8 4 6
2 5 1
1 6 2
0.4 6 2
Now I want to code that MATLAB sums up the values of the 1st column in the rows where the value of the 2nd and 3rd column match.
So the result should look like this below:
0.2 2 3
1 3 4
1.8 4 6
2 5 1
1.4 6 2
I hope someone can help me, thank you!

3 Kommentare

Bob Thompson
Bob Thompson am 23 Jan. 2019
"where the value of the 2nd and 3rd column match."
How do the values of the 2nd and 3rd column match in any of these rows?
In general form this should be fairly easy with logic indexing.
yinki23
yinki23 am 23 Jan. 2019
Sorry if I was unspecific.
For example, rows no.3 and no.4 both have 4 and 6 in columns no.2 and no.3. So I want to sum these 2 rows up in column 1 (1+0.8). Same with rows no.6 and no.7.
I hope this helps you understand my question.
James Tursa
James Tursa am 23 Jan. 2019
Are the values in columns 2 and 3 always positive integers?

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 Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 23 Jan. 2019

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A = [0.2 2 3
1 3 4
1 4 6
0.8 4 6
2 5 1
1 6 2
0.4 6 2];
[a,~,c] = unique(A(:,2:3),'rows','stable');
out = [accumarray(c,A(:,1)),a];

Weitere Antworten (1)

s
s am 23 Jan. 2019

0 Stimmen

clc;
clear all;
A = [0.2 2 3;1 3 4;1 4 6;0.8 4 6;2 5 1;1 6 2;0.4 6 2];
B = size (A,1);
Result = [];
n = 0;
for i = 1:1:B-1
if (A(i,2) == A(i+1,2) && A(i,3) == A(i+1,3))
n = n+1;
end
end
for j = 1:1:B-n
if (A(j,2) == A(j+1,2) && A(j,3) == A(j+1,3))
Sum = A(j,1)+A(j+1,1);
Result = [Result; Sum A(j,2) A(j,3)]
A([j+1],:) = [];
else
Result = [Result; A(j,1) A(j,2) A(j,3)]
end
end
This should help

Gefragt:

am 23 Jan. 2019

Beantwortet:

s
s
am 23 Jan. 2019

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