Why does Matlab say my function is undefined?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
So I have the following code
x=input('Enter the value x from the interval pi/6 to pi/2:');
while x<pi/6 || x>pi/2
disp(fprintf('Please enter an x value from the specified interval of pi/6 to pi/2 \n'))
x=input('Enter the value x from the interval pi/6 to pi/2:');
if x>pi/6 || x<pi/2
continue
end
end
n=input('Enter an integer for two, three, or four terms:');
while n~=2 || n~=3 || n~=4
disp(fprintf('You already entered that number or you entered an incorrect choice.\n'))
n=input('Enter an integer for two, three, or four terms:');
if n==2
y=func2(x);
Y=fprcall(x,n,y)
elseif n==3
y=func3(x);
Y=fprcall(x,n,y)
elseif n==4
y=func4(x);
Y=fprcall(x,n,y)
else
disp(fprintf('You already entered that number or you entered an incorrect choice.\n'))
end
end
function y=func2(x)
y=x-((x^3)/(factorial(3)));
end
function y=func3(x)
y=x-((x^3)/(factorial(3)))+((x^5)/(factorial(5)));
end
function y=func4(x)
y=x-((x^3)/(factorial(3)))+((x^5)/(factorial(5)))-((x^7)/(factorial(7)));
end
function Y=fprcall(x,n,y)
z=sin(x);
RE= (100*(y-sin(x)))/sin(x);
fprintf('For x=%0.4f and n=%f the values are y=%0.6f, sin(x)=%0.6f, and RE=%0.4f\n',x,n,y,z,RE)
end
For some reason when I run it for lets say when n=3, the function I have will not run. This occurs for all of them. Is there anything I am missing?
0 Kommentare
Antworten (1)
Kelly Kearney
am 27 Nov. 2018
If you strip out most of the commands, the main structure of your code looks like this:
n=input('Enter an integer for two, three, or four terms:');
while n~=2 || n~=3 || n~=4
% do stuff
end
So, you ask your user to enter 2, 3, or 4... but then only execute your commands if the user starts by entering an incorrect choice.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Structures finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!