Find ∑(xi+i)2 for i=4 to 163
xi represents the 'i'th value in the list of x values.
This is what I have coded...
x=0;
for i=4:163;
x=(x+x(i)).^2;
end
x
But it says this:
Index exceeds the number of array elements (1).
Error in (line 31)
x=(x+x(i)).^2;

Antworten (2)

madhan ravi
madhan ravi am 21 Nov. 2018
Bearbeitet: madhan ravi am 21 Nov. 2018

0 Stimmen

x is only defined as a scalar value which is zero so when you try to acess 2nd element it gives an error. Cumsum/symsum is recommended for your case.

1 Kommentar

Sarah Baki-Hashemi
Sarah Baki-Hashemi am 21 Nov. 2018
I'm not familiar with those functions. I have just been trying to use many simplier functions to obtain the answer.

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Walter Roberson
Walter Roberson am 21 Nov. 2018
Bearbeitet: Walter Roberson am 21 Nov. 2018

0 Stimmen

i = 4:163;
sum( (i+x(i)).^2)
This expects x to already have been defined

2 Kommentare

Torsten
Torsten am 21 Nov. 2018
I think you mean "i" instead of "ii".
Walter Roberson
Walter Roberson am 21 Nov. 2018
Dang new editor doubles single characters in mobile access .

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