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gauss forward interpolation method

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PJS KUMAR
PJS KUMAR am 18 Okt. 2018
Bearbeitet: Torsten am 18 Okt. 2018
I wrote the following code for gauss interpolation
function [ yval ] = gauss_p( xd,yd,xp )
n=length(xd);
if(length(yd)==n)
tbl=yd';
for j=2:n
for i=1:n-j+1
tbl(i,j)=tbl(i+1,j-1)-tbl(i,j-1);
end
end
tbl
h=xd(2)-xd(1);
if rem(n,2)==0
k=n/2+1;
else
k=n/2+0.5;
end
p=(xp-xd(k))/h
pt=cumprod([1,p-(0:n-3)])
dt=[tbl(k,1) tbl(k,2) tbl(k-1,3)+tbl(k-1,4) tbl(k-1,4)+tbl(k-1,5) tbl(k-1,5)+tbl(k-1,6) tbl(k-1,6)+tbl(k-1,7)]./factorial(0:n-2)
yval=sum(pt.*dt)
end
Suggest me to simplify the calculation of 'dt' vector subject to 'n' values

Antworten (1)

Torsten
Torsten am 18 Okt. 2018
Bearbeitet: Torsten am 18 Okt. 2018
dt = [tbl(k,1), tbl(k,2), tbl(k-1,3:n-1)-tbl(k-1,4:n)]./factorial(0:n-2)
?
Best wishes
Torsten.

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