Substitution problem in matlab
4 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Michael Elman
am 13 Sep. 2018
Kommentiert: madhan ravi
am 13 Sep. 2018
Hello, I'm new in matlab, and I'm trying to learn operations with variables,so I have encountered a little problem, that I don't quite understand, why
ER=subs(yp,{sx},{1})
ER=subs(yp,{sy},{1})
it's not a same thing, as
ER=subs(yp,{sx,sy},{1,1})
? In first case the answer is
-y*(exp(-x^2/sx^2)*exp(-y^2) - 1)
(and I don't want sx^2) and in the second case the answer is
-y*(exp(-x^2)*exp(-y^2) - 1)
(this is exactly, what i need)
This is my starting code:
syms x y z;
syms sx sy;
yp=y*(1-exp(-x^2/sx^2)*exp(-y^2/sy^2))
Does someone know what's the reason behind it?
1 Kommentar
madhan ravi
am 13 Sep. 2018
Bearbeitet: madhan ravi
am 13 Sep. 2018
Can you format the code by selecting the whole code and clicking the code button?
Akzeptierte Antwort
madhan ravi
am 13 Sep. 2018
Bearbeitet: madhan ravi
am 13 Sep. 2018
syms x y z;
syms sx sy;
yp=y*(1-exp(-x^2/sx^2)*exp(-y^2/sy^2))
ER=subs(yp,{sx},{1})
ER=subs(ER,{sy},{1})
ER1=subs(yp,{sx,sy},{1,1})
Reason: when you wanted to substitute for sy the second time you should type ER instead of up because you’re replacing the old equation again
TYPE:
ER=subs(ER,{sy},{1})
INSTEAD OF:
ER=subs(yp,{sy},{1})
2 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Number Theory finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!