Index exceeds matrix dimensions

When I run the following code, matlab shows me an error that the index exceeds matrix dimensions. It seems like it has an easy solution, but I am still relatively new to matlab and coding in general.

Some background info if required, I'm trying to validate a thermal model and x2 is reduced temperature and yp is predicted thermal efficiency. p1 and p2 depict my thermal coefficients.

Hope you can help me out!

k1 -> constant

x2 -> 100x1 (double)

p1 = [0:0.1:10]; %100 elements

p2 = [0:0.001:1]; %1000 elements

for m=1:length(p1)

      for n=1:length(p2)

          yp(m,n) = ((k1.*p2(m,n))./(p1(m,n)+p2(m,n)))-((x2(m,n).*(p1(m,n).*p2(m,n)))./(p1(m,n)+p2(m,n)));

      end       
  end

Answer 1

[madhan ravi]

k1 = 30

x2= [1:100]'

p1 = linspace(0,10,100); %100 elements

p2 = linspace(0,1,100); %100 elements

P=p1+p2

PP = p1.*p2

          yp = ((k1*p2)./(P))-((x2.*(PP))./(P))

[madhan ravi]

NOTE : x2 and k were given as examples.

The error arises because p1 and p2 aren't equal in dimensions.

There is no need for loop here.

[Shiwankar Garg]

Thanks madhan! Yes you were right, there is no need for a loop here, and your code worked till some extent.

Any idea how I can make it work for varying element sizes of p1 and p2?

[madhan ravi]

I’m not sure of it but what I know is if the sizes of p1 and p2 vary you can’t add them because there will be some mismatches. What you can do is you can add zeros to the vector which is deficient of elements so that both the vectors will have the same length.

[madhan ravi]

An example:

v1 = [1:8 zeros(1,2)]

v2 = [1:10]

V = v1+v2

[Shiwankar Garg]

Thanks a lot madhan, will test it out. Vector addition should work.