Why the block "Three-Phase Series RLC Load" creates the current values twice as much on each phase?
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Frequency: 50Hz. Nominal phase-to-phase voltage of Source: Unom(ph-ph)=400(V). Nominal phase voltage of Source: Unom(ph)=400/(3^0.5)=230.940(V). Nominal phase-to-phase voltage of Load in Volts RMS: 400/(2^0.5)=282.843(Vrms). Active power of Load: P=576e3(W). Inductive reactive power of Load: QL=300e3(var). Capacitive reactive power of Load: Qc=21.03e3(var). By calculation through known equation we get apparent power:S=[P^2+(QL-Qc)^2]^0.5=640e3(VA).Then we can get the current value per phase: I=S/[Unom(ph-ph)*3^0.5]=924(A). In Amperes RMS: Irms=I/(2^0.5)=653(Arms). In according with measuring current value in Amperes RMS obtaining from amperemeter (current measurement) and shown at displays, we get twice as much phase current: 1306(Arms). Although on calculation conducted phase current must be 653(Arms).
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/191299/image.jpeg)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/191300/image.jpeg)
0 Kommentare
Antworten (1)
Joel Van Sickel
am 2 Sep. 2020
Hello Murat,
for your model, you are simulating with a 400V peak to peak line voltage. However, your calculations are for a 400V RMS line voltage.
Regards,
Joel
Siehe auch
Kategorien
Mehr zu Switches and Breakers finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!