Question about plotting matrix

Hello I have problem in plotting (2*2) loop matrix. My matrice code is as follow :

theta=0:pi/6:2*pi;
A=[cos(theta), 0 ; 0,sin(theta)];

I need to plot the matrix for each theta value, in my case there is 7 iterations (theta=0:pi/6:2*pi), it means 7 values of theta and 7 resulting matrices for each value of theta. For theta=0; A=[1, 0 ; 0, 0]; .... For theta=2*pi; A=[1, 0 ; 0, -2.4493e-16];

plot(A)  
plot(A,'o')

I need to plot all the values of A, but ploting dont give inside values.

[Dennis]

Why 7 values for theta? You move from 0 to 2*pi in steps of pi/6, resulting in 13 values? You will only have 1 matrix A. This matrix has 2 columns with 14 entries each (13 calculated values and a zero).

 theta=0:pi/6:2*pi;
 A=[cos(theta);sin(theta)]

 plot(theta,A(1,:))
 hold on
 plot(theta,A(2,:))

[Rik]

What do you mean with plotting this matrix? Should one row be considered x-coordinate and the other y-coordinate? Should all values be plotted against their column position (which would result in two lines if you had chosen a line format)?

[Aakash Deep]

You can not directly plot a matrix but if your data is stored in a matrix you have to plot row/column vectors individually. The variable theta don't store 7 values, there are 13 values in 0:pi/6:2*pi, if you want 7 values in this range use linspace instead.

Answer 1

[Ameer Hamza]

We need to get all the values of matrix A in every iteration and plot them not the final values.

close all
clear all
clc
for a = 0:pi/6:2*pi;
r = 2;
x = sin (a);
y = cos(a);
z = r*(x+y);
A = [z 0 0;0 z 0;0 0 z];
disp (A)
plot (A, 'o')
end

[Dennis]

So you want 13 plots? How do you want to plot A? How does a [2 0 0; 0 2 0; 0 0 2] plot look like? You want to have a 3D plot?