I have a vector: a = [1 5 7 2 6 8 9 0 2] and b=[5 8 1 0 3 6 9 8 2] (both have the same size) I want to sort vector 'a' and accordingly vector 'b'.
a = [1 5 7 2 6 8 9 0 2] ;
b = [5 8 1 0 3 6 9 8 2] ;
[a1,ind]=sort(a) for i=1:length(a1)
b1(1,i)=b(1,ind(1,i));
end
It works. But I am wondering if there is a more professional way to get ride of this "for i=1:length(a1)" loop?
Thanks in advance.

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Oleg Komarov
Oleg Komarov am 1 Jun. 2012

2 Stimmen

Simply
b(ind)

1 Kommentar

Andrea
Andrea am 1 Jun. 2012
wow, Thanks. It is the briefest, fastest and cutest answer I've ever got!

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