Hello, I am trying to include the following simple code as one of my constraints in my optimization model:
if Xij = 1, then Xik=0 for all k not equal j.
Please assist. Cheers

Antworten (1)

dpb
dpb am 15 Apr. 2018
Bearbeitet: dpb am 15 Apr. 2018

0 Stimmen

One way; may be more better...presuming X is square...
is1=(X==1);
X(is1 & ~eye(size(X)))=0;
Oh!...easy enough if isn't square, too...
is1=(X==1);
X(is1 & ~eye(min(size(X))))=0;

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am 15 Apr. 2018

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dpb
am 15 Apr. 2018

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