How to use pdeplot with appdesigner?

6 Ansichten (letzte 30 Tage)
JClarcq am 5 Apr. 2018
I try to display a gradient contour from a thermal pde solution.
as expected it displays a new figure. Thus I tried
like I would do for normal plot. But that is not supported. Is there a solution?
  1 Kommentar
Mohammad reza Nejati
Mohammad reza Nejati am 4 Mär. 2020
I have the same problem. could anyone help please ?

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Antworten (2)

Ruben Gavín Mulelro
Ruben Gavín Mulelro am 29 Mai 2021
Same problem.. Have you found any solution?

Angelo Hafner
Angelo Hafner am 14 Jul. 2019
Today I was working all day looking for an answer. It folows my code...
nt = 21;
r = linspace(r1,r2,nt);
th = linspace(0,2*pi,nt);
[R,TH] = meshgrid(r,th);
% polar to cartezian (may be not necessary in your case
X = R .* cos(TH);
Y = R .* sin(TH);
The important thing here is to do the meshgrid
querypoints = [X(:),Y(:)]';
uintrp = interpolateSolution(results,querypoints);
and here is reshape
uintrp = reshape(uintrp,size(X));

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