sum
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
i have an array whose size is 467*320 = 149440 i mean,
Y = [y1 y2 ... y149440] and i'd like to do that :
Y_1 =[y1+y2+y3...+y320 y321+y322+y321+...y640 .....]
y11=y1+y2+...+y320
y12=y321+y322...+y640
:
:
that is to say; the first element of Y_1 is sum of the first 320 elements and the second element of that is sum of the second 320 elements and going on like this and the size of Y_1 will be 1x467(1x149440/320)...
And i will have Y_2 like Y_1
for Y_2 : Y_2=[y1+y2+y3+...+y320 ..... .... ](1x467)
y21=y1+y2+y3+...+y320
:
:
at the end i create X-array that is
X = [y11+y21 y12+y22 y13+y23 ......]
this is my question :)
i thank you for your helps...
0 Kommentare
Akzeptierte Antwort
Matt Fig
am 23 Mär. 2011
I am a little confused, do you mean like this:
Y = reshape(1:18,6,3) % A manageable dimension.
Y_1 = sum(Y,2)
So in your case it would be
Y_1 = sum(Y,2).';
.
.
Or do you mean, more like this:
Y = 1:18
Y_1 = sum(reshape(Y,3,6))
So in your case it would be
Y_1 = sum(reshape(Y,320,467))
4 Kommentare
Matt Fig
am 23 Mär. 2011
So then my second example is the solution to your problem, correct?
Y = rand(1,149440);
Y_1 = sum(reshape(Y,320,467));
size(Y_1)
ans =
1 467
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Multidimensional Arrays finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!