Order cell array
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I have this cell array http://dl.dropbox.com/u/59868217/fileList.mat. Can I sort the array with respect to the number of characters that compose the file name? Cioè is possible obtain the array like this
'tot16/57583.raw'
'tot16/213587.raw'
'tot16/369571.raw'
'tot16/681550.raw'
'tot16/837534.raw'
'tot16/993529.raw'
'tot16/1149513.raw'
I obtain this list of file by this script function fileList = getAllFiles(dirName)
dirData = dir(dirName); %# Get the data for the current directory
dirIndex = [dirData.isdir]; %# Find the index for directories
fileList = {dirData(~dirIndex).name}'; %'# Get a list of the files
if ~isempty(fileList)
fileList = cellfun(@(x) fullfile(dirName,x),... %# Prepend path to files
fileList,'UniformOutput',false);
end
subDirs = {dirData(dirIndex).name}; %# Get a list of the subdirectories
validIndex = ~ismember(subDirs,{'.','..'}); %# Find index of subdirectories
%# that are not '.' or '..'
for iDir = find(validIndex) %# Loop over valid subdirectories
nextDir = fullfile(dirName,subDirs{iDir}); %# Get the subdirectory path
fileList = [fileList; getAllFiles(nextDir)]; %# Recursively call getAllFiles
end
end
1 Kommentar
Akzeptierte Antwort
Geoff
am 15 Mai 2012
There's a couple of ways to do this... I assume you want the numbers in ascending order. This works, but relies on the stability of sort():
fileList = sort(fileList);
[~,I] = sort(cellfun(@length, fileList));
fileList = fileList(I);
The proper way to do it is:
n = cellfun(@(x) str2double(x{:}), regexp(fileList, '/(\d+)\.raw', 'tokens'));
[~, I] = sort(n);
fileList = fileList(I);
This converts the filenames to numbers, finds the sort order and rearranges the list accordingly.
5 Kommentare
Geoff
am 16 Mai 2012
That exact code works on the exact file list you provided. Did you type it in, or did you copy and paste it from my answer?
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