Sum specific intervals of rows for a matrix
19 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Timo
am 20 Feb. 2018
Kommentiert: Maryam S
am 28 Feb. 2019
Hello everybody,
I know there are some similar posts regarding the topic but I was not able to solve my problem.
I have a matrix a=53320x228 and wanted to calculate the sum in intervals of 12 for each row (f.e. sum of elements 1:12,13:24... for each row), so that my output would be a 53320x19 matrix as each row has 19*12 elements. In the past I was always able to handle similar problems with:
reshape(sum(reshape(...)))
or
sum(reshape())
But unfortunately, this time I did not recognize how it will work. Other topics related to the problem also suggest to use reshape but it doesn't produce the desired results.
Hopefully someone could help me out, I would really appreciate each hint.
0 Kommentare
Akzeptierte Antwort
Aveek Podder
am 23 Feb. 2018
Hi,
I believe you want to sum the 12 consecutive columns of a Matrix and convert it to one column. Doing this Matrix a of size 53320x228 results to a 53320x19 Matrix.
You need to shape the Matrix into a 53320x12x19 Matrix. Then you have to do column summation and reshape the matrix back to 5330x19 Matrix.
Please have a look at the following code:
B = reshape(a,53320,12,19);
C = sum(B,2);
out = reshape(C,53320,19);
Hope this helps.
2 Kommentare
Weitere Antworten (1)
Danielle Torp
am 31 Okt. 2018
I have a follow up to this problem- If i wanted to calculate sums in intervals of differing lengths because each column has differing number of rows (i.e. column a = 100 rows, column b = 90 rows), but I want to reshape so each column only has 10 rows (which are sums of equal intervals per column).
3 Kommentare
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!