According to SVD technique A=U*S*V'. But when I apply SVD to my image, I am not able to retrieve my original image. Is that because S matrix is not taking the all the eigen values? Eventhough, I had to get a partially correct image?
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Sandra Maria Cherian
am 20 Feb. 2018
Kommentiert: Sandra Maria Cherian
am 20 Feb. 2018
[u,s,v]=svd(a); ap=u*s; a=ap*v;
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Roger Stafford
am 20 Feb. 2018
Bearbeitet: Roger Stafford
am 20 Feb. 2018
You've left off the transpose operator at the last step:
ap*v';
It's a very small character, but it's all-important!
Round-off errors may cause tiny differences between your original a and the restored a. If the image pixels in the original a were all integers, just do a round on the result and that should restore it exactly.
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