Why does the second example fail?

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Derrick Salmon
Derrick Salmon am 13 Feb. 2018
Kommentiert: Derrick Salmon am 14 Feb. 2018
here's my code and the response
testvec = [Xc,Yc,sig,A]
ErrTest1 = RMS_Err_func(Image,Xc,Yc,sig,A)
ErrTest2 = RMS_Err_func(Image,testvec)
gives:
ErrTest1 =
0.0942
Not enough input arguments.
Error in NM_2D_Gauss_fit>RMS_Err_func (line 60)
r(l,m) = sqrt((l-Xc).^2+(m-Yc).^2);
Error in NM_2D_Gauss_fit (line 46)
ErrTest2 = RMS_Err_func(Image,testvec)
  3 Kommentare
Derrick Salmon
Derrick Salmon am 13 Feb. 2018
Walter
Is there no way for the function so see the contents of testvec?
Walter Roberson
Walter Roberson am 13 Feb. 2018
... Yes?
You are passing it in to the function, so the second argument can examine the contents of testvec.

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Walter Roberson
Walter Roberson am 13 Feb. 2018
I suspect that your testvec is a vector that has within it values for Xc, Yc, sig, A . If so then,
temp = num2cell(testvec);
ErrTest2 = RMS_Err_funct(Image, temp{:});

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