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can you please explain the working of following syntax?
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z=D{extrema(4*(i-1)+1)}(rx,ry,rz);
it is continuously giving 'Bad cell reference operation.' error.
extrema=zeros(1,4*number);
idx= extrema==0;
extrema(idx)=[];
extr_volume=length(extrema)/4;
for i=1:extr_volume
x=floor((extrema(4*(i-1)+3)-1)/(n/(2^(extrema(4*(i-1)+1)-2))))+1;
y=mod((extrema(4*(i-1)+3)-1),m/(2^(extrema(4*(i-1)+1)-2)))+1;
rx=x+1;
ry=y+1;
rz=extrema(4*(i-1)+2);
z=D{extrema(4*(i-1)+1)}(rx,ry,rz);
size(z)
if(abs(z)<threshold)
extrema(4*(i-1)+4)=0;
end
end
0 Kommentare
Antworten (1)
Star Strider
am 14 Jan. 2018
The code you posted does not make sense. It sets ‘extrema’ to an empty array, so all references to elements of ‘extrema’ would throw errors, because they do not exist.
3 Kommentare
Star Strider
am 14 Jan. 2018
I cannot run the code that you attached.
I will delete my Answer in a few hours.
Walter Roberson
am 14 Jan. 2018
We do not have your b.jpg to test with. I copied the demo image car2.jpg to b.jpg and ran the code without difficulty.
"Bad cell reference operation" is not a MATLAB error message. Is it possible that you were running under Octave?
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