Index exceeds matrix dimensions problem with this code below :-

18 Ansichten (letzte 30 Tage)
c =
1 1 1 6
2 4 2 16
-1 5 -4 -3
N = length(c);
tol= 1e-6;
for ii=1:N-1
for jj=ii+1:N
if abs(c(jj,ii))> tol
fac=c(ii,ii) / c(jj,ii);
c(jj,:) = fac*c(jj,:) - c(ii,:);
end
end
end
how to solve this problem? that code for Gauss elimination when I press enter it appear " Index exceeds matrix dimensions "

Akzeptierte Antwort

ANKUR KUMAR
ANKUR KUMAR am 7 Jan. 2018
c =[1 1 1 6; 2 4 2 16; -1 5 -4 -3]
N = size(c,1)
M=size(c,2)
tol= 1e-6;
for ii=1:M-1
ii
for jj=ii+1:N
jj
if abs(c(jj,ii))> tol
fac=c(ii,ii) / c(jj,ii);
c(jj,:) = fac*c(jj,:) - c(ii,:);
end
end
end
Instead of writing length(c), you should to define the size along first and second dimension of matrix, i.e. define the number of row and columns of matrix.

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 7 Jan. 2018
length() of a 3 x 4 array is 4. length() is not the number of rows: length() is defined as:
  • 0 if any dimension of the array is 0; or
  • max() of size() of the array otherwise.

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