comparision of database images

I have folder name database and under this 400 images are there,they are named as s1_1,s1_2......s1_10 then s2_1,s2_2....s2_10 so on upto s40_1,s40_2....s40_10 . I would like to compare each image with other 399 images.Those folder contains the extracted images using SIFT features. I tried but could not come up with an efficient code. So, could someone please suggest me an idea or code at least how to read those images.

Answer 1

[KALYAN ACHARJYA]

% Please save all images name in symmetrically before doing the operation 
 % names for example im1,im2,im3...
 % Pls ensure both folder images having equal numbers of images to compare one by one
 %Save the folder of images in the current directory
 path_directory='optha_original'; % 'Folder name'
 % Pls note the format of images,change it as required
 original_files=dir([path_directory '/*.jpg']); 
 l=1;
 for k=1:length(original_files)
    filename=[path_directory '/' original_files(k).name];
    image_orginal=imread(filename);
    % Image read is done
    %%Following code for Image Call
    images_call='images1'; % 'Folder name'
    call_files=dir([images_call '/*.gif']); % Alert: Image format
    filename=[images_call '/' call_files(l).name];
    l=l+1; % This increment for next call images
    call_image=imread(filename);
   % Now you have two images image_orinal>original image
   % and call_image> call image for compare
   % Next do your operation and finding
end