Filter löschen
Filter löschen

comparing the maximum value of a matrix to the other values

5 Ansichten (letzte 30 Tage)
SSG_newbiecoder
SSG_newbiecoder am 29 Dez. 2017
Kommentiert: SSG_newbiecoder am 29 Jan. 2018
Hello, I have a question. I need to compare the maximum value in an array to the other elements in an array and check if it is greater than 1.2 times the other elements. How can I do this in matlab? I'd prefer it if it is a simple command since I'm already doing this within a loop. I know max will give me the maximum but how to compare it with the other elements?

Antworten (2)

KSSV
KSSV am 29 Dez. 2017
A = randperm(10,5) ;
B = randperm(20,5) ;
iwant = max(A)/max(B)
fprintf('max of A is %f times to max of B\n',iwant)
  4 Kommentare
SSG_newbiecoder
SSG_newbiecoder am 29 Dez. 2017
I have an array X=[1 2.2 3.5 3.8 2.8 2.9]. Maximum is 3.8. But I need to check if this maximum is 1.2 times the other 5 elements in the array.
KSSV
KSSV am 29 Dez. 2017
X=[1 2.2 3.5 3.8 2.8 2.9] ;
R = X./max(X) ;
idx = abs(R-1.2)<10^-3

Melden Sie sich an, um zu kommentieren.


Walter Roberson
Walter Roberson am 29 Dez. 2017
If you want to know whether it is greater than 1.2 for all of the elements, then
if max(FirstArray) > 1.2 * max(SecondArray)
If you want to know whether it is greater than 1.2 for some element then
if max(FirstArray) > 1.2 * min(SecondArray)
I recommend that you explicitly comment the behavior you want when some of the values in the second array might be negative. Is -1.3 "greater than" 1.2 times -1 because the value has greater distance from 0 ?
  5 Kommentare
SSG_newbiecoder
SSG_newbiecoder am 29 Jan. 2018
Or if you can suggest a method to find an array element that is 1.2 times that of the other elements in the array, that will solve the problem without all the above hassle

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by