How to vectorize this nested loop for optimized performance

3 Ansichten (letzte 30 Tage)
Yodish
Yodish am 18 Dez. 2017
Kommentiert: Matt J am 19 Dez. 2017
hello everybody, I have been trying to optimize this nested for loop which is very very slow, but with no success
for i=1:size(Sxx,2)-1
for j=1:size(Sxx,2)-1
A=Sxx(:,i).*conj(Sxx(:,j));
B= (ifft(A, 'symmetric'));
[~, T(i,j)] = max(B(1:round(end/2)));
end
end
any help is appreciated!

Akzeptierte Antwort

Matt J
Matt J am 18 Dez. 2017
Bearbeitet: Matt J am 19 Dez. 2017
My advice would be not to vectorize it completely (although there are ways to do so), but rather reduce it to one loop as below.
[m,n]=size(Sxx);
k=1:round(m/2);
SxxConj=conj(Sxx(:,1:n-1));
T=nan(n-1);
for i=1:n-1
B=ifft(Sxx(:,i).*SxxConj, [],1,'symmetric'); %If <R2016b use bsxfun
[~,T(i,:)]=max(B(k,:),[],1); %EDITED
end
You could also convert this to a parfor loop if the serial performance is insufficient.
  1 Kommentar
Matt J
Matt J am 19 Dez. 2017
Comment by Yodish:
Definitely faster (probably not enough yet though for my purposes) and more elegant, thanks Matt
PS. index of B needs to be swapped in second last line

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by