how can i represent 3d surface(conical surface) by using surface vector function
9 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
can özbaran
am 17 Dez. 2017
Kommentiert: can özbaran
am 18 Dez. 2017
xw=10;
qg=2*pi;
qw=1;
lw=0:pi/12:pi/2;
x=(xw+qw*sin(lw))*cos(qg);
y=(xw+qw*sin(lw))*sin(qg);
z= qw*(1-cos(lw));
hi everyone ,
i want to represent 3d surface by using those vector equations(equation should be represent conical surface) but i couldnt achieve yet. i use "meshgrid" and "surf" command but i couldnt do it.
Can anybody help me with these problem ?
0 Kommentare
Akzeptierte Antwort
Roger Stafford
am 18 Dez. 2017
Bearbeitet: Roger Stafford
am 18 Dez. 2017
You should be using the results of meshgrid to calculate Z so that it will be a matrix, not a vector. As near as I can make out, your conical vertex is located at a point (3*cot(pi/5),0,0). Try this:
fic = pi/5;
u = linspace(0,8);
q = linspace(0,2*pi);
[U,Q] = meshgrid(u,q);
X = 3*cot(fic)-(U.*cos(Q))*cos(fic);
Y = (U.*sin(Q))*cos(fic);
Z = U*sin(fic);
surf(X,Y,Z)
I may not have guessed correctly as to your intended cone location, orientation, or angle, but this code should give some pointers about how to obtain the result you desire.
Weitere Antworten (1)
Siehe auch
Kategorien
Mehr zu Surface and Mesh Plots finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!