Why do I get the error "Too many input arguments"
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my_recorder = audiorecorder;
recordblocking(my_recorder,2)
x= getaudiodata(my_recorder);
LPF0=LPF;
x0=filter(LPF0,Num_LPF,1,x);
Code written above is my matlab code.
But when I activated this, "Too many input arguments" message is shown on the command window.
How can I solve this problem?
function Hd = LPF
% MATLAB Code
% Generated by MATLAB(R) 9.2 and the Signal Processing Toolbox 7.4.
% Generated on: 08-Dec-2017 11:47:53
% Equiripple Lowpass filter designed using the FIRPM function.
% All frequency values are in Hz.
Fs = 48000; % Sampling Frequency
Fpass = 200; % Passband Frequency
Fstop = 300; % Stopband Frequency
Dpass = 0.057501127785; % Passband Ripple
Dstop = 0.0001; % Stopband Attenuation
dens = 20; % Density Factor
% Calculate the order from the parameters using FIRPMORD.
[N, Fo, Ao, W] = firpmord([Fpass, Fstop]/(Fs/2), [1 0], [Dpass, Dstop]);
% Calculate the coefficients using the FIRPM function.
b = firpm(N, Fo, Ao, W, {dens});
Hd = dfilt.dffir(b);
% [EOF]
and this is my LPF.
2 Kommentare
KSSV
am 8 Dez. 2017
Which line shows the error? How did you run the code? It doesn't show any error in my pc.
Antworten (1)
Honglei Chen
am 8 Dez. 2017
It should just be
x0=filter(LPF0,x);
the coefficients is already in LPF0.
HTH
1 Kommentar
Abhinaba Dey
am 11 Mär. 2018
Error using filter2 Too many input arguments.
Error in find_sift (line 48) I_X = filter2(G_X, I, 'same'); % vertical edges
I get the same error. How can I solve it??
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