Also, every time I run the for loop again, matrices A1 and B1 reduce their dimension...this shouldn't happen
if statement does not execute the statements
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Maria445
am 14 Okt. 2017
Kommentiert: Star Strider
am 14 Okt. 2017
I can't understand what I'm doing wrong here; basically I have two matrices, A and B, and if one of the two matrices has a row in which every entry is equal to NaN, I want to delete the corresponding row in the other matrix as well. This is the code I used:
A1 = A;
B1 = B;
for i = 1 : size(A,1)
if sum(isnan(A(i,2:end)))==size(A(:,2:end),2) || ...
sum(isnan(B(i,2:end)))==size(B(:,2:end),2);
A1(i,:) = []
B1(i,:) = [];
end
end
However, in matrix B1 there are still many rows entirely made of NaN values. Why is this not working?
Akzeptierte Antwort
Star Strider
am 14 Okt. 2017
If I understand correctly what you want to do, this should work:
A = randi(9, 7, 4); % Create Matrices
B = randi(9, 7, 4); % Create Matrices
A([2 6],:) = NaN; % Create ‘NaN’ Rows In ‘A’
B(4,:) = NaN; % Create ‘NaN’ Rows In ‘B’
row_idx = all(isnan(A),2) | all(isnan(B),2); % Logical Index For ‘NaN’ Rows In Both
A(row_idx,:) = []; % Delete Rows In ‘A’
B(row_idx,:) = []; % Delete Rows In ‘B’
2 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!