Hi trying to set specific date ticks. I don't understand why the following code does not work
figure()
hold on
box on
plot(date1,series1,'k')
plot(date1,series2,'r--')
xlabel('Date')
ylabel('Price')
DateString = {'06/30/2010';'11/30/2010'};
datenum(DateString);
set(gca, 'XTick', datenum(DateString))
dateFormat = 1;
datetick('x', dateFormat)

 Akzeptierte Antwort

Walter Roberson
Walter Roberson am 13 Okt. 2017

1 Stimme

datetick('x', dateFormat, 'keepticks')

5 Kommentare

EM
EM am 13 Okt. 2017
Hi Walter, are you implying that the only adjustment I need is to include 'keepticks' ?
Walter Roberson
Walter Roberson am 13 Okt. 2017
Yes. datetick() normally ignores any tick positions already set and calculates "nice" tics based upon the time format. So use the 'keepticks' option.
Setting the tick positions after calling datetick() would not work: datetick() sets the tick labels to strings, and those strings would not be reflect the positions you set afterwards.
plotting with datetime objects is even better; datetick was always a bit of a kludge.
EM
EM am 13 Okt. 2017
Thank you!
EM
EM am 21 Okt. 2017
Hi I'm still receiving an error. Can you help?
Here is the code:
figure()
hold on
box on
plot(date1,series1,'k')
plot(date1,series2,'r--')
xlabel('Date')
ylabel('Price')
DateString = {'06/30/2010';'11/30/2010'};
datenum(DateString);
set(gca, 'XTick', datenum(DateString))
dateFormat = 1;
datetick('x', dateFormat,'keepticks')
Here is the error:
Error using matlab.graphics.axis.decorator.DatetimeRuler/validateTicks Value must be a vector of increasing datetime values.
Error in matlab.graphics.axis.decorator.DatetimeRuler/setTicksDelegate
Your date1 appears to be datetime objects, and you appear to be using R2016b or later. In that case you do not use datetick.
figure()
hold on
box on
plot(date1, series1, 'k')
plot(date1, series2, 'r--')
xlabel('Date')
ylabel('Price')
DateString = {'06/30/2010';'11/30/2010'};
ticlocs = datetime(DateString); %R2014b or later
ticlocs.Format = 'dd-MMM-yyyy';
set(gca, 'XTick', ticklocs); %R2016b or later

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Weitere Antworten (2)

Peter Perkins
Peter Perkins am 13 Okt. 2017
Bearbeitet: Walter Roberson am 13 Okt. 2017

3 Stimmen

If you have access to R2016b or later, you will probably be much happier using datetime rather than datenum/datestr, including for plotting:
d = datetime(2015,1,1:500);
x1 = randn(size(d));
plot(d,x1)
ax = gca;
ax.XAxis.TickValues = datetime(2015,1,1)+calquarters(0:6);
ax.XAxis.TickLabelFormat = 'QQQ-yyyy';

3 Kommentare

EM
EM am 13 Okt. 2017
Can you use this approach to place ticks at specific dates? For example I have 8 specific dates that I'd like to place a tick at. So I cannot simply use a start date and increase it by quarters.
Yup. For example,
ax.XAxis.TickValues = datetime(2015,1,1)+days([18 143 207 258]);
ax.XAxis.TickLabelFormat = 'MMM dd';
or
ax.XAxis.TickValues = datetime(2015,[1;5;11;14], [17;5;30;19]);
ax.XAxis.TickLabelFormat = 'yy/M/d';
EM
EM am 13 Okt. 2017
Thank you Walter, that is very helpful.

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Med Aymane Ahajjam
Med Aymane Ahajjam am 14 Mai 2019

0 Stimmen

In order for the TickLabelFormat to work, at least in my case, I had to specify:
ax.XTickLabelMode = 'manual';
ax.XAxis.TickLabelFormat = 'HH:mm:ss';

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