error with optimisation

Hi, I was looking to do optimization for this http://4.bp.blogspot.com/-WSb8BrAmc9w/T5Hy2QaXJqI/AAAAAAAAAac/ZwDB5y19jAs/s1600/toric_optimization.jpg shape. I was wondering if someone could kindly point out my errors in this code:
% objective function for optimization
function F = toric_opt_obj(XX)
global alpha11 alpha12 alpha21 alpha22 alpha0
global icount
alpha11 = XX(1);
alpha12 = XX(2);
alpha21 = XX(3);
alpha22 = XX(4);
alpha0 = XX(5);
icount = icount + 1;
toric_obstacle;
% (x_1^2+x_2^2)^2+alpha12*x_1^2+alpha22*x_2^2+alpha11*x_1+alpha21*x_2+alpha0=0
toric =(z1.^2+z2.^2).^2+alpha12.*z1.^2+alpha22.*z2.^2+alpha11.*z1+alpha21.*z2+alpha0;
L1 = length(z1);
L2 = length(z2);
if z2 == -1*ones(1,L2)
Err_1 = toric - z1;
end
if (z2 == .8*ones(1,L2) && (-1.2*ones(1,L1) <z1< -.5*ones(1,L1)))
Err_2 = toric - z2;
end
if z2 == .5*ones(1,L2)
Err_3 = toric - z1;
end
if (z2 == .8*ones(1,L2) && (.6*ones(1,L1) <z1< 1.2*ones(1,L1)))
Err_4 = toric - z2;
end
Err = Err_1^2 + Err_2^2 + Err_3^2 + Err_4^2;
% Err = (z1.^2+z2.^2).^2+alpha12*z1.^2+alpha22*z2.^2+alpha11*z1+alpha21*z2+alpha0;
F = norm(Err); %error square root of the sum of the error squared
[icount XX F]
this part of code is right which is
% Minimum error - toric section
clear all; clc;
global alpha11 alpha12 alpha21 alpha22 alpha0
alpha11 = 0;
alpha12 = -2;
alpha21 = .2;
alpha22 = -1.5;
alpha0 = .5;
% initial limity cycle shape
ii0 = 0;
for x10=-1.5:.01:1.5
x20 = roots([1 0 (2*x10^2+alpha22) alpha21 (alpha0+alpha11*x10+alpha12*x10^2+x10^4)]);
for ii=1:4
if isreal(x20(ii))
ii0 = ii0 + 1;
x1lci(ii0) = x10;
x2lci(ii0) = x20(ii);
end
end
end
XX0 = [alpha11 alpha12 alpha21 alpha22 alpha0];
lb = [-.1 -3 .01 -2 .3];
ub = [ .1 -1 .40 -1 .7];
optionso = optimset('LargeScale','off','MaxFunEvals',150);
%norm_tol = .01;
%icount = 0;
% [XX,fval,exitflag,output] = fmincon(@objfun,XX0,[],[],[],[],lb,ub,@confun,optionso)
[XX,fval,exitflag,output] = fminsearch(@toric_opt_obj,XX0)
alpha11 = XX(1);
alpha12 = XX(2);
alpha21 = XX(3);
alpha22 = XX(4);
alpha0 = XX(5);
%alpha22=-2.124;
% optimal limity cycle shape
ii0 = 0;
for x10=-1.5:.01:1.5
x20 = roots([1 0 (2*x10^2+alpha22) alpha21 (alpha0+alpha11*x10+alpha12*x10^2+x10^4)]);
for ii=1:4
if isreal(x20(ii))
ii0 = ii0 + 1;
x1lco(ii0) = x10;
x2lco(ii0) = x20(ii);
end
end
end
toric_obstacle;
figure (1)
plot(z1,z2,'k-',x1lci,x2lci,'b*',x1lco,x2lco,'ro','LineWidth',2);
legend('obstacle','initial','optimal');
and this is my obstacle m-file:
% obstacle definition
x0 = -1.2;
y0 = -1;
x1 = -0.6;
y1 = -0.5;
x2 = 0.6;
x3 = 1.2;
y3 = 0.8;
delta = 0.01;
%line 1
i = 0;
for x = x0:delta:x3
i = i + 1;
z1(i) = x;
z2(i) = y0;
end
%line 2
i = i - 1;
for y = y0:delta:y3
i = i + 1;
z1(i) = x3;
z2(i) = y;
end
%line 3
i = i - 1;
for x = x3:-delta:x2
i = i + 1;
z1(i) = x;
z2(i) = y3;
end
%line 4
i = i - 1;
for y = y3:-delta:y1
i = i + 1;
z1(i) = x2;
z2(i) = y;
end
%line 5
i = i - 1;
for x = x2:-delta:x1
i = i + 1;
z1(i) = x;
z2(i) = y1;
end
%line 6
i = i - 1;
for y = y1:delta:y3
i = i + 1;
z1(i) = x1;
z2(i) = y;
end
%line 7
i = i - 1;
for x = x1:-delta:x0
i = i + 1;
z1(i) = x;
z2(i) = y3;
end
%line 8
i = i - 1;
for y = y3:-delta:y0
i = i + 1;
z1(i) = x0;
z2(i) = y;
end
i = i - 1;
z1 = z1(1:i);
z2 = z2(1:i);

4 Kommentare

Walter Roberson
Walter Roberson am 21 Apr. 2012
In the picture, how can the optimal path go right through an obstacle ??
Villanova
Villanova am 21 Apr. 2012
Well, good question. I actually made the U shaped obstacle later on. The blue curve is a toric section and the alpha parameters were identified by trial and error. For now, I am more concerned to make sure the red curves become something similar to the blue ones, that wave the robot could take that path.
Walter Roberson
Walter Roberson am 21 Apr. 2012
So the obstacle shown in the image should be treated as not being there?
Anyhow, you are going to have to indicate what the error you observe _is_ . Error message, traceback ?
Villanova
Villanova am 24 Apr. 2012
I get this error message:
??? Operands to the || and && operators must be convertible to logical
scalar values.
Error in ==> toric_opt_obj at 24
if (z2== .8*ones(1,L2) && (-1.2*ones(1,L1) <z1< -.5*ones(1,L1)))
Error in ==> fminsearch at 205
fv(:,1) = funfcn(x,varargin{:});

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 Akzeptierte Antwort

Walter Roberson
Walter Roberson am 24 Apr. 2012

0 Stimmen

Use & instead of && .
Read the documentation for all() and any()
a < b < c is interpreted as (a < b) < c . The first part produces a logical value, 0 or 1, and it is that logical value that is compared to c. Consider using (a < b & b < c)

Weitere Antworten (2)

Villanova
Villanova am 26 Apr. 2012

0 Stimmen

I also have this error :(
Undefined function or variable "Err_1".
Error in ==> toric_opt_obj at 36
Err = Err_1^2 + Err_2^2 + Err_3^2 + Err_4^2;

3 Kommentare

Walter Roberson
Walter Roberson am 26 Apr. 2012
You have several variables that you only give a value to if an "if" statement condition is true. If the "if" condition is not true, the variables go undefined.
Did you fix the "if" statement conditions to repair the "==" and all()/any() problems ?
Villanova
Villanova am 26 Apr. 2012
yes i did change the errors by && in the if statements.
Walter Roberson
Walter Roberson am 26 Apr. 2012
Please show the current code for the "if" lines, including the current version of
if z2 == -1*ones(1,L2)
Please also show L2, and size(z2)

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Villanova
Villanova am 26 Apr. 2012

0 Stimmen

hi the if was ok i believe. the only thing wrong seemed to be &&. So I didn't change much: this is the new one:
function F = toric_opt_obj(XX)
global alpha11 alpha12 alpha21 alpha22 alpha0
global icount
alpha11 = XX(1);
alpha12 = XX(2);
alpha21 = XX(3);
alpha22 = XX(4);
alpha0 = XX(5);
icount = icount + 1;
toric_obstacle;
% (x_1^2+x_2^2)^2+alpha12*x_1^2+alpha22*x_2^2+alpha11*x_1+alpha21*x_2+alpha0=0
toric =(z1.^2+z2.^2).^2+alpha12.*z1.^2+alpha22.*z2.^2+alpha11.*z1+alpha21.*z2+alpha0;
L1 = length(z1);
L2 = length(z2);
if z2 == -1*ones(1,L2)
Err_1 = toric - z1;
end
if (z2 == .8*ones(1,L2) & (-1.2*ones(1,L1) <z1< -.5*ones(1,L1)))
Err_2 = toric - z2;
end
if z2 == .5*ones(1,L2)
Err_3 = toric - z1;
end
if (z2 == .8*ones(1,L2) & (.6*ones(1,L1) <z1< 1.2*ones(1,L1)))
Err_4 = toric - z2;
end
Err = Err_1^2 + Err_2^2 + Err_3^2 + Err_4^2;
% Err = (z1.^2+z2.^2).^2+alpha12*z1.^2+alpha22*z2.^2+alpha11*z1+alpha21*z2+alpha0;
F = norm(Err); %error square root of the sum of the error squared
[icount XX F]

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