On looping over drawnow

3 Ansichten (letzte 30 Tage)
Alvin
Alvin am 4 Okt. 2017
Kommentiert: Alvin am 4 Okt. 2017
clear
C1 = 20000;
C2 = linspace(0,26,5500);
k1 = 0.5;
k2 = 5;
n1 = 0;
n2 = 0;
nm = 0;
D = -1;
O = 1;
gam = 0.01;
alph = 0;
for ii=1:length(C2)
w = linspace(-10,10,5500);
k1eff = k1.*(1+C2);
TA = w./(k1eff./2);
TB = w./(gam./2);
Y1 = (-2.*1i.*sqrt(C1))./(sqrt(gam).*((1+C2).*(1-1i.*TA).*(1-1i.*TB)+C1));
Y2 = (-2.*sqrt(C1.*C2))./(sqrt(gam).*((1+C2).*(1-1i.*TA).*(1-1i.*TB)+C1));
Y3 = (2.*(1+C2).*(1-1i.*TA))./(sqrt(gam).*((1+C2).*(1-1i.*TA).*(1-1i.*TB)+C1));
AY1 = abs(Y1).^2;
AY2 = abs(Y2).^2;
AY3 = abs(Y3).^2;
Sbb = 2*pi.*(AY1.*(n1 + 0.5) + AY2.*(n2 + 0.5) + AY3.*(nm + 0.5));
figure(1)
plot(TB,Sbb)
drawnow limitrate
%ylim([0,30])
set(gca,'FontSize',13)
xlabel('\Theta_B')
ylabel('S_{bb}')
%ylim([0,5])
end
I am trying to plot my Sbb as a function of TB for each step of the loop. Upon executing the code above however I see a curve with two peaks with different heights but the graph isn't changing over time. Much help would be appreciated. Thank you in advance.

Akzeptierte Antwort

the cyclist
the cyclist am 4 Okt. 2017
Nothing in your for loop depends on the loop variable ii, so why would you expect the plot to change?
  1 Kommentar
Alvin
Alvin am 4 Okt. 2017
Indeed, I am the silliest. I've managed to fix it. Thank you.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Graphics Performance finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by