The complex number integration

2 Ansichten (letzte 30 Tage)
lick liao
lick liao am 13 Sep. 2017
Kommentiert: Star Strider am 14 Sep. 2017
I have some complex number integration to solve.
Here is my equation: z=exp^(j*2*pi*f) H=(abs(2*z^(-1)-z^(-2)))^2
I want to calculate the integtion of H from f=0 to f=a
I use the int(), but it only return the function I write. It seems it can't calculate out the answer.
Is someone who know how to deal with the problem? Thank for your reply!

Akzeptierte Antwort

Star Strider
Star Strider am 13 Sep. 2017
I would eliminate the abs call until the end, using it on the integrated function only after you evaluate it numerically.
Try this:
syms a f real
z(f) = exp(1j*2*pi*f);
H(f) = (2/z - 1/z^2)^2;
H = rewrite(H, 'sincos'); % Optional, If You Want a Trigonometric Result
IH = int(H, f, 0, a);
IH = simplify(IH, 'Steps', 20)
  2 Kommentare
lick liao
lick liao am 14 Sep. 2017
Bearbeitet: lick liao am 14 Sep. 2017
Thanks a lot.
You give me another way to think about the equation.
I transfer H(z) to trigonometric form, then get the final answer.
Star Strider
Star Strider am 14 Sep. 2017
As always, my pleasure.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Mathematics finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by